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IMPLEMENT A FINDNODE METHOD Action 3 Create a new FindNode method. Note: This method accepts a file name and returns the matching TreeNode object, if any. This also accepts a boolean value indicating whether to expand the node. This feature will come in handy later in the chapter. 4 Make sure the selected node is not null. Note: This value should never be null, but it is always good to check. 5 If expandNode is true, make sure the contents of the selected node are loaded into the tree. Find the node that matches the given string.

In this example, the placeholder types type1 and type2 are replaced by the compiler with the data types int and char * and double and long, respectively, when the compiler generates the specific instances of myfunc( ) within main( ) Remember: When you create a generic function, you are, in essence, allowing the compiler to generate as many different versions of that function as necessary to handle the various ways that your program calls that function

Table B10 ISO 639 Language Codes (continued)

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// Ensure contents of node are available if (expandNode) node.Expand(); TreeNode node = treeViewMain.SelectedNode; if (node == null) return null;

Even though a template function overloads itself as needed, you can explicitly overload one, too If you overload a generic function, then that overloaded function overrides (or hides ) the generic function relative to that specific version For example, consider this version of swapargs( ):

private TreeNode FindNode (string fileName, bool expandNode) {

// Overriding a template function #include <iostream> using namespace std; template <class X> void swapargs(X &a, X &b) { X temp; temp = a; a = b; b = temp; } // This overrides the generic version of swap() void swapargs(int &a, int &b) { int temp; temp = a; a = b; b = temp; cout << "Inside overloaded swapargs(int &, int &)\n"; } int main() { int i=10, j=20; float x=101, y=233; char a='x', b='z'; cout << "Original i, j: " << i << ' ' << j << endl; cout << "Original x, y: " << x << ' ' << y << endl; cout << "Original a, b: " << a << ' ' << b << endl; C++

639-1 ml Hex 4D4C Dec 7776 Language Name Makasar Malayalam Mandingo Austronesian Marathi Masai Moksha Mandar Mende Irish, Middle (900-1200) Mi kmaq; Micmac Minangkabau Uncoded languages Macedonian Mon-Khmer Malagasy Maltese Manchu Manipuri Manobo languages Mohawk Moldavian; Moldovan Mongolian Mossi Maori Malay Multiple languages Munda languages Creek Mirandese Marwari Burmese Mayan languages Erzya Nahuatl languages North American Indian Neapolitan Nauru Navajo; Navaho Ndebele, South; South Ndebele Ndebele, North; North Ndebele Ndonga Low German; Low Saxon; German, Low; Saxon, Low Nepali

a. For each child of the selected node, find the file associated with the node. b. If a match is found, return it to the caller. 7 If no match is found, return

swapargs(i, j); // this calls the explicitly overloaded swapargs() swapargs(x, y); // swap floats swapargs(a, b); // swap chars cout << "Swapped i, j: " << i << ' ' << j << endl; cout << "Swapped x, y: " << x << ' ' << y << endl; cout << "Swapped a, b: " << a << ' ' << b << endl; return 0; }

As the comments indicate, when swapargs(i, j) is called, it invokes the explicitly overloaded version of swapargs( ) defined in the program Thus, the compiler does not generate this version of the generic swapargs( ) function because the generic function is overridden by the explicit overloading Recently, a new-style syntax was introduced to denote the explicit specialization of a function This new method uses the template keyword For example, using the new-style specialization syntax, the overloaded swapargs( ) function from the preceding program looks like this:

// Search for a matching node foreach (TreeNode n in node.Nodes) { string nodePath = n.Tag as string; if (nodePath == fileName) { // Found it! return n; }

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// Use new-style specialization syntax template<> void swapargs<int>(int &a, int &b) { int temp; temp = a; a = b; b = temp; cout << "Inside specialized swapargs(int &, int &)\n"; }

} return null;

As you can see, the new-style syntax uses the template<> construct to indicate specialization The type of data for which the specialization is being created is placed inside the angle brackets following the function name This same syntax is used to specialize any type of generic function While there is no advantage to using one specialization syntax over the other, the new-style is probably a better approach for the long term Manual overloading of a template, as shown in this example, allows you to specially tailor a version of a generic function to accommodate a special situation In

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