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three_d operator+(three_d op2) ; friend ostream &operator<<(ostream &stream, three_d &obj); operator int() { return x*y*z; } } ; // Display X, Y, Z coordinates - three_d inserter ostream &operator<<(ostream &stream, three_d &obj) { stream << objx << ", "; stream << objy << ", "; stream << objz << "\n"; return stream; // return the stream } three_d three_d::operator+(three_d op2) { three_d temp(0, 0, 0); tempx tempy tempz return } int main() { three_d a(1, 2, 3), b(2, 3, 4), c(0, 0, 0); cout << a << b; cout << b+100; // displays 124 because of conversion to int cout << "\n"; c = a+b; // adds two objects cout << c; return 0; } = x+op2x; = y+op2y; = z+op2z; temp; // these are integer additions // and the + retains its original // meaning relative to them

1, 2, 3 2, 3, 4 124 3, 5, 7

CREATE A SHARED PIXELDLG INSTANCE Action 1 In the PixelDlg.cs code window, create static members to hold the shared instance and an MDI parent form, if any. Create an internal property to assign and retrieve an MDI container form. Create a public property to retrieve the shared form.

As the program illustrates, when a three_d object is used in an integer expression, such as cout << b+100, the conversion function is applied to the object In this specific case, the conversion function returns the value 24, which is then added to 100 However, when no conversion is needed, as in c = a+b, the conversion function is not called Remember that you can create different conversion functions to meet different needs You could define one that converts to double or long, for example Each is applied automatically

j ISO 3901:1986 Documentation - International Standard Recording Code (ISRC) j IFPI SID CODE Implementation Guide

static private Form _mdiForm = null; static private PixelDlg _globalDlg;

By default, when one object is used to initialize another, C++ performs a bitwise copy That is, an identical copy of the initializing object is created in the target object Although this is perfectly adequate for many cases and generally exactly what you want to happen there are situations in which a bitwise copy cannot be used One of the most common situations in which you must avoid a bitwise copy is when an object allocates memory when it is created For example, assume two objects, A and B, of the same class called ClassType, which allocates memory when creating objects, and assume that A is already in existence This means that A has already allocated its memory Further, assume that A is used to initialize B, as shown here ClassType B = A; If a bitwise copy is performed, then B will be an exact copy of A This means that B will be using the same piece of allocated memory that A is using, instead of allocating its own Clearly, this is not the desired outcome For example, if ClassType includes a destructor that frees the memory, then the same piece of memory will be freed twice when A and B are destroyed! The same type of problem can occur in two additional ways: first, when a copy of an object is made when it is passed as an argument to a function; and second, when a temporary object is created as a return value from a function (Remember, temporary objects are automatically created to hold the return value of a function, and they may also be created in certain other circumstances)

static internal Form GlobalMdiParent { get { return _mdiForm; } set { _mdiForm = value; } } static public PixelDlg GlobalDialog { get { if (_globalDlg == null || _globalDlg.IsDisposed) { _globalDlg = new PixelDlg(); _globalDlg.MdiParent = GlobalMdiParent; } return _globalDlg; } }

26:

(see Table B10)

You can have a switch as part of the statement sequence of an outer switch Even if the case constants of the inner and outer switch contain common values, no conflicts arise For example, the following code fragment is perfectly acceptable:

The GlobalDialog property provides the mechanism by which all child MainForm instances can access the same PixelDlg form. Recall that our PixelDlg form is MDI CHILDREN 549

switch(x) { case 1: