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Let s look at another example to help clarify the six steps For step 1, you are given the following address and subnet mask: 1921681132 255255255192 (/26), which is a Class C address Remember the shortcut from earlier: if the last octet is even, it s either a network or host address Therefore, you know it s not a directed broadcast address In the second step, you need to find the interesting octet in the subnet mask This is the last octet For a Class C network, this will always be the last octet The value in this mask is 192, indicating that the first two high-order bits in the octet are part of the network component and the last six low-order bits are the host component In step 3, you need to determine by what number the network addresses are increasing To do this step, subtract the value in the subnet mask s interesting octet from 256: 256 192 = 64 Therefore, network addresses are incrementing by 64 numbers and each network contains 64 addresses: a network address, a directed broadcast address, and 62 host addresses Remember that since the interesting octet is in the fourth octet, the network addresses are increasing by 64 in the interesting (fourth) octet In step 4, write down the network numbers In our example, this gives you four networks: 19216810, 192168164, 1921681128, and 1921681192 In the interesting octet, 2 bits are used for networking and 6 bits for host addresses With 2 bits of networking, this gives you four networks (22 = 4), and with 6 bits of host addresses and 64 addresses in a network, it s 26 = 64 The address in question, 1921681132, is between two networks: 1921681128 and 1921681192 This means that you should have to perform steps 5 and 6 only on these two networks, and possibly the network before it However, go ahead and complete steps 5 and 6 for all of the networks since this is good practice Remember that the directed broadcast address for a network is one number less than the next network number and that the addresses between the network and directed broadcast addresses are host addresses Table 7-10 shows the addressing for the Class C address Our address, 1921681132, is a host address based on this table, where its network number is 1921681128 and its directed broadcast is 1921681191.

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TABLE 7-10

Network, Broadcast, Directed, and Host Addresses of 19216810/26

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To examine the active or running configuration on an IOS device, use the show running-config command You must be in Privilege EXEC mode to execute this command Here is an example of this command from a Cisco router:

Router# show running-config Building configuration Current configuration: ! version 120 no service udp-small-servers no service tcp-small-servers ! hostname Router

Notice the references to Building configuration and Current configuration in this example Both of these refer to the configuration in RAM

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Configuration files are stored in NVRAM for both switches and routers When an IOS device boots up, the IOS operating system loads the configuration from NVRAM and places it in RAM However, as mentioned in the Running and Startup Configuration introduction to this section, the running configuration in RAM is not automatically saved to NVRAM: if you turn off your IOS device without saving its configuration, your newly implemented changes will disappear To save the active configuration to NVRAM, you must execute the copy running-config startup-config Privilege EXEC mode command Upon executing this command, the IOS device takes the active configuration in RAM and saves it to NVRAM In this process, the old configuration file in NVRAM is overwritten Here is an example of this command:

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IOS# copy running-config startup-config Destination filename [startup-config] Building configuration [OK] IOS#

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