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As you can see, each catch statement responds only to its own type In general, catch expressions are checked in the order in which they occur in a program Only a matching statement is executed All other catch blocks are ignored

// Update the appropriate Tag property if (item != null) { item.Tag = newFileName; if (node != null) node.Text = newName; } else if (node != null) node.Tag = newFileName; return true; }

You need to be careful how you order your catch statements when trying to catch exception types that involve base and derived classes because a catch clause for a base class will also match any class derived from that base Thus, if you want to catch exceptions of both a base class type and a derived class type, put the derived class first

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private bool UpdatePhotoCaption (string caption, object obj) { ListViewItem item = obj as ListViewItem; TreeNode node = obj as TreeNode; // Determine the album index int index = -1; if ((item != null) && (item.Tag is int)) { index = (int)item.Tag; node = FindNode(_album[index].FileName, false); } else if (node != null) { index = node.Index; }

in the catch sequence If you don t do this, the base class catch will also catch all derived classes For example, consider the following program

// Catching derived classes #include <iostream> using namespace std; class B { }; class D: public B { }; int main() { D derived; try { throw derived; } catch(B b) { cout << "Caught a base class\n"; } catch(D d) { cout << "This won't execute\n"; } return 0; }

a. Change the second parameter to an object rather than a ListViewItem. b. Convert the given object to both a list item and a tree node. c. Determine the album index for the appropriate object. d. If the object is a list view item, also find the node corresponding to this item. 10 Return false if the caption cannot be updated.

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Here, because derived is an object that has B as a base class, it will be caught by the first catch clause and the second clause will never execute C++ Builder will flag this condition with a warning message To fix this condition, reverse the order of the catch clauses

if ((caption.Length == 0) || (index < 0)) { MessageBox.Show("Invalid caption value."); return false; }

#include <ctypeh> #include <stdioh> int main(void) { char ch; for(;;) { ch = getchar(); if(ch==' ') break; if(ispunct(ch)) printf("%c is punctuation\n", ch); } return 0; }

SUPPORT EDITING OF TREE NODE LABELS (continued) Action 11 Update the photograph s caption, and save the changes to the album. Note: When the object is a list item, this updates the corresponding node as well.

isalnum( ), iscntrl( ), isalpha( ), isdigit( ), isgraph( ), isspace( )

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int isspace(int ch)

// Update caption _album[index].Caption = caption; if (item != null && node != null) { // Update node text as well node.Text = caption; } // Save the changes to the album . . .

The prototype for isspace( ) is found in <ctypeh> The isspace( ) macro returns non-0 if ch is either a space, carriage return, horizontal tab, vertical tab, form feed, or newline character; otherwise, it returns 0

Our program now permits editing of nodes in the TreeView and items in the ListView. Editing is initiated with the menuLabelEdit menu or the F2 key, and is based on which control currently has the focus. In both update methods, note how the as keyword is used to convert the given object into both a TreeView and a ListView, as is shown in the following excerpt. The remainder of each method executes the appropriate statements based on which type of control is provided.

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This program checks each character read from stdin and reports all those that are white-space characters:

ListViewItem item = obj as ListViewItem; TreeNode node = obj as TreeNode;

#include <ctypeh> #include <stdioh> int main(void) { char ch; for(;;) { ch = getchar(); if(ch=='') break;

if(isspace(ch)) printf("%c is white-space\n", ch); } return 0; }